What is the percent chance of one of the children having a homozygous genotype?

What is the percent chance of one of the children having a homozygous genotype?

• A. 25%
• B. 50%
• C. 75%
• D. 100%

Answer: (B)

To determine the percent chance of one of the children having a homozygous genotype, it's important to understand the principles of genetics, specifically focusing on allele combinations during inheritance. When two parents each contribute alleles for a particular gene, they can be either homozygous (two identical alleles, such as AA or aa) or heterozygous (two different alleles, such as Aa). The potential combinations arise from how these alleles combine. If one assumes both parents are heterozygous (Aa), then the possible genotypes for their children would be: - AA (homozygous dominant) - Aa (heterozygous) - aa (homozygous recessive) From a Punnett square analysis of Aa x Aa, you would observe the following distributions: - 25% are expected to be AA (homozygous dominant) - 50% are Aa (heterozygous) - 25% are aa (homozygous recessive) In this scenario, focusing on the homozygous genotype as a category (either AA or aa), you find that there is a total of 50% chance that a child will be homozygous (both AA and aa combine to equal

To determine the percent chance of one of the children having a homozygous genotype, it's important to understand the principles of genetics, specifically focusing on allele combinations during inheritance.

When two parents each contribute alleles for a particular gene, they can be either homozygous (two identical alleles, such as AA or aa) or heterozygous (two different alleles, such as Aa). The potential combinations arise from how these alleles combine.

If one assumes both parents are heterozygous (Aa), then the possible genotypes for their children would be:

• AA (homozygous dominant)

• Aa (heterozygous)

• aa (homozygous recessive)

From a Punnett square analysis of Aa x Aa, you would observe the following distributions:

• 25% are expected to be AA (homozygous dominant)

• 50% are Aa (heterozygous)

• 25% are aa (homozygous recessive)

In this scenario, focusing on the homozygous genotype as a category (either AA or aa), you find that there is a total of 50% chance that a child will be homozygous (both AA and aa combine to equal